· 10 years ago · Apr 06, 2016, 03:15 PM
1@Entity
2
3private static final long serialVersionUID = 1L;
4
5@Id
6@GeneratedValue(strategy=GenerationType.AUTO)
7@Column(name="id")
8private int id;
9
10@Column(name="teamId")
11private int teamId;
12
13//private String Rentabiliteit;
14
15@Column
16//@Index(name="IProject_status",columnNames="Status")
17private String status;
18
19@Column
20//@Index(name="IProject_naam",columnNames="Naam")
21private String naam;
22//public Prototype m_Prototype;
23//public Team m_Team;
24
25public Project(){
26
27CREATE TABLE IF NOT EXISTS `project` (
28`id` int(11) NOT NULL,
29`teamId` int(11) DEFAULT NULL,
30`status` varchar(255) DEFAULT NULL,
31`naam` varchar(255) DEFAULT NULL
32 ) ENGINE=InnoDB AUTO_INCREMENT=43 DEFAULT CHARSET=latin1;
33
34Caused by: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException:
35 Unknown column 'project0_.team_id' in 'field list'
36
37spring:
38
39mvc:
40 view:
41 prefix: /WEB-INF/jsp/
42 suffix: .jsp
43
44datasource:
45 url: jdbc:mysql://localhost:3306/oxyplast
46 username: oxyplastuser
47 password: oxyplastuserpw
48
49jpa:
50 properties:
51 hibernate:
52 current_session_context_class: org.springframework.orm.hibernate4.SpringSessionContext
53 namingStrategy: org.hibernate.cfg.DefaultNamingStrategy
54
55@column(name=""teamId"")
56
57private int teamId;